Electromagnetic transmission summary
Electromagnetic transmission summary
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Electromagnetic transmission summary
Electric Power Transmission
Power: P= E/t
Power is a measure of the rate of transfer (transmission) or transformation of energy: P = E/t . Transfer (transmission) occurs when energy of one kind is moved from one object/place to another. Transformation occurs when energy of one kind is changed into another kind of energy. Power is measured in Watts, ‘W’, and is equal to one Joule per Second, ‘Js-1’.
Electric Power: P= IV = q/t * E/q = E/t
Electrical power is transmitted when a voltage, ‘V’, across a component results in a current, ‘I’, through that component. This is because the voltage is a measure of the electrical energy, ‘E’, transferred or transformed by each unit of charge, ‘q’, and the current is a measure of the rate of transfer of unit charges: ‘q/t’.
Electrical Dissipation (Transmission Losses):V= IR
In ohmic devices, such as conductors, the current through a component depends on the voltage across it and the resistance, ‘R’, of that component. Resistance, measured in ohms, W, is a measure of the tendency of a component to dissipate the energy that is transmitted through it. Dissipation is the transformation of energy of one kind (e.g., electrical energy) into heat energy. This relation, V=IR, is known as ‘Ohm’s Law’.
Power Loss: Ploss= I2R = V2/R
The rate at which energy is transformed from electrical to heat energy in a conductor (and therefore lost from the electrical circuit) depends on the product of the square of the current through the conductor and the resistance of the conductor:
Ploss= I2R. That is, the power loss from a conductor is proportional to both the current and the resistance: the higher the current or resistance the more power is lost.
P= IV, V= IR,
.: P= I·IR = I2R
Alternately, Power lost is proportional to the square of the voltage across a conductor per unit of resistance: P = V2/R. That is, the same amount of voltage across a conductor will result in less power loss as the resistance is increased!
P= IV, V= IR, I = V/R,
.: P = V· V/R = V2/R
This is a less intuitive way of understanding the causes of power loss so the first formula, P= I2R, is safer to use for calculations.
Electrical Power Transformers
The need for transformers:RTseries= nRei
Electrical Power is often generated a long way away (e.g., Gippsland) from where it will eventually be used (e.g., Melbourne). This means that it needs to be transmitted through long conductors. Short (e.g., one meter long) conductors have a low resistance (e.g., 0.02 Wm-1). Longer conductors (e.g., 100 km) may be considered to be made up of many (e.g., 100,000) low resistance resistors (e.g., 0.02 W) in series. The total effective resistance of series resistors is the sum of the individual resistors: RTseries= SRi. For multiple equal resistances: RTseries= nRei (e.g., 100,000 x 0.02 = 2000 W = 2 kW). This will make power loss significant. To transmit electric power a very high voltage is needed, but to use this power a much lower voltage is needed. Transformers can be used to make these changes to the voltage of an alternating current.
Operation of a Transformer:np /ns = Vp /Vs = Is/Ip
A transformer is made up of two coils of wire wrapped around opposite sides of a hollow square/ring of iron. When one of the coils (the primary coil) is connected to an alternating current (AC) source it will produce a changing magnetic field inside the iron core, according to the Faraday-Lenz Law: e = –n Df/Dt. This will then produce a changing magnetic field inside the other coil (the secondary coil) which will induce a voltage/current in that coil: again according to the Faraday-Lenz Law: e = –n Df/Dt. If the area of the two coils is equal (as usual), then the rate of flux, Df/Dt = –ep /np, produced by the primary coil will be the equal to the rate of flux,Df/Dt = –es /ns, produced in the secondary coil.
.: –ep /np = –es /ns , .: ep /np = es /ns
.: ep /es = np /ns , P= IV, V= e = P/I,
.: np /ns = (Pp/Ip) / (Ps/Is), Pp = Ps,
.: np /ns = (1/Ip) / (1/Is) = Is/Ip,
The ratio of primary-to-secondary coils is proportional to the ratio of the voltages and inversely to the ratio of the currents.
Transformers with np > ns, are step-down, np < ns, are step-up.
Ideal versus Real Transformers
These relations are true because we assumed that there was no power loss within the transformer: Pp = Ps. In reality there is always some (usually small) power loss: Pp > Ps. Some of this loss will be due to the resistance of the coils (Ploss= I2R) and some will be due to eddy currents (induced electron motion) in the iron core.
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